A presidential election was held in Pennsylvania on October 30, 1840 as part of the 1840 United States presidential election.[1] Voters chose 30 representatives, or electors to the Electoral College, who voted for President and Vice President.

Pennsylvania voted for Whig challenger William Henry Harrison over Democratic incumbent Martin Van Buren by just 334 votes, a margin of 0.12%. It is the narrowest margin of victory in a presidential election in Pennsylvania history, with Donald Trump's 2016 win following close behind at 0.72%.

Results

1840 United States presidential election in Pennsylvania[2]
Party Candidate Votes Percentage Electoral votes
Whig William Henry Harrison 144,010 49.99% 30
Democratic Martin Van Buren (incumbent) 143,676 49.89% 0
Liberty James G. Birney 340 0.12% 0
Totals 288,026 100.0% 30

See also

References

  1. ↑ Dubin, Michael J. (2002). United States Presidential Elections, 1788–1860: The Official Results by County and State. Jefferson, NC: McFarland & Co. p. xvi.
  2. ↑ "1840 Presidential General Election Results - Pennsylvania". U.S. Election Atlas. Retrieved August 4, 2012.


source: https://en.wikipedia.org/wiki/1840_United_States_presidential_election_in_Pennsylvania